if (i == num.length - 1 || num[i] != num[i + 1] || prev.size() == 0) { Explanation: There is no possible combination such that the array can be divided into two subsets, such that they have the equal sum. An array A is a subset of an array B if a can be obtained from B by deleting some (possibly, zero or all) elements. Subsets II By zxi on May 16, 2019 Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). if (i == num.length - 1 || num[i] != num[i + 1]) { }. result.add(new ArrayList()); Medium. Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). prev.add(new ArrayList(result.get(j))); We just combine both into our result. LeetCode 90 Subsets II, Coding Interview Question Level : Medium Challenge : 9/1000 Given a collection of integers that might contain duplicates, nums , return all possible subsets (the power set). Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Summary: //add each single number as a set, only if current element is different with previous Note: The solution set must not contain duplicate subsets. DO READ the post and comments firstly. Feed the method [1,2,3] the following will be result at each iteration. https://www.youtube.com/watch?v=XtJ-dpLmK4Y, This solution is for array contains duplicates numbers: Explanation: The sum of the first and second elements equals the third element. This is the best place to expand your knowledge and get prepared for your next interview. ArrayList> prev = new ArrayList>(); The solution set must not contain duplicate subsets. [LeetCode] Subsets 解题报告 Given a set of distinct integers, S, return all possible subsets. LeetCode Word Subsets Solution Explained - Java - Duration: 15:41. Recursive … for (int i = num.length-1; i >= 0; i--) { Programming Loops vs Recursion - Computerphile - … ), n is the number of elements of the given nums. //add current number to each element of the set Elements in a subset must be in non-descending order. If S = [1,2,3], a solution is:eval(ez_write_tag([[250,250],'programcreek_com-medrectangle-3','ezslot_1',136,'0','0'])); Comparing this problem with Subsets can help better understand the problem. Example: Notice - Elements in a subset must be in non-descending order. GoodTecher LeetCode Tutorial 78. ... when n=2, subsets: {}, {"1"}, {"2"}, {"1", "2"} Subsets II: Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Subsets. - The solution set must not contain duplicate subsets. Auxiliary Space: O(sum*n), as the size of 2-D array is sum*n. Subset Sum Problem in O(sum) space Perfect Sum Problem (Print all subsets with given sum) Please write comments if you find anything incorrect, or … For example, leetcode Question 105: Subsets II Subsets II. for (ArrayList temp : prev) { } List result = new ArrayList(); Hey What exactly is difference between the 2 questions subset and subset II ?? Let's get started: I'll be solving this problem using 2 techniques: … Note: Elements in a subset must be in non-descending order. This problem has time complexity of O(2^n), since finding all subsets of a set is a NP problem. The solution set must not contain duplicate subsets. Subsets Solution; How to identify? This problem is the base to solving other problems like subset sum and subset partitioning which I'll be discussing in coming posts. 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